0=2.5x-4.905x^2+5.2

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Solution for 0=2.5x-4.905x^2+5.2 equation: 



0=2.5x-4.905x^2+5.2

We move all terms to the left:

0-(2.5x-4.905x^2+5.2)=0

We add all the numbers together, and all the variables

-(2.5x-4.905x^2+5.2)=0

We get rid of parentheses

4.905x^2-2.5x-5.2=0

a = 4.905; b = -2.5; c = -5.2;
Δ = b2-4ac
Δ = -2.52-4·4.905·(-5.2)
Δ = 108.274
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{108.274}}{2*4.905}=\frac{2.5-\sqrt{108.274}}{9.81}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{108.274}}{2*4.905}=\frac{2.5+\sqrt{108.274}}{9.81}
$

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